xiphias: (Default)
xiphias ([personal profile] xiphias) wrote2008-11-02 09:36 pm
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Talking to my father tonight, he brought up an interesting concept

Okay. So, apparently, a black hole does not actually need to be super-dense. It's just, the less dense it is, the bigger its radius has to be in order for it to be a black hole.

A solar-system-sized black hole would only need to be about as dense as air. If you made a big sphere the size of the orbit of Neptune, and filled it with air -- that'd be a black hole.

Here's the weird thought. Um. Not that that previous thing ISN'T a weird thought. But here's a weirder one:

The density of the intergalactic medium is probably something like one hydrogen atom per cubic meter. Not very dense.

But nonetheless, a density.

That means that there exists a radius such that the entire universe is a black hole. And it's calculable.

Which puts an upper bound on the size of the universe. And leaves the possibility that our entire universe is, in fact, on the black hole side of an event horizon.

[identity profile] mabfan.livejournal.com 2008-11-03 02:54 am (UTC)(link)
Carl Sagan mentioned something like this on the Cosmos TV show. I remember a scene of him standing in the woods on a sunny day, and saying, "If you want to know what's like inside a black hole, look around you."

[identity profile] wcg.livejournal.com 2008-11-03 02:57 am (UTC)(link)
Yeah, we talked about this in my graduate cosmology class. There's absolutely no reason to believe we're not inside a black hole.

[identity profile] gilmoure.livejournal.com 2008-11-03 03:00 am (UTC)(link)
I'm not sure how this is supposed to work. I mean, a black hole is a gravity gradient at the point where it's 'too steep' for light to escape, isn't it? How does this correlate with density? I mean, I understand that, the denser something is, the steeper it's gravity field but wouldn't expanding it's radius result in a less steep gravity slope and then you wouldn't have a singularity/Schwartzchild Radius?

[identity profile] xiphias.livejournal.com 2008-11-03 03:23 am (UTC)(link)
You DO have a Schwartzchild radius. It's just very, very big.
brooksmoses: (Default)

[personal profile] brooksmoses 2008-11-03 07:22 am (UTC)(link)
No, you've got that backwards. His Schwartzchild radius is teeny-tiny, much smaller than he is, and since he's not all within that radius, he's not a black hole.

However, there is an amount of mass which, if packed into a sphere with the same density he has, would be a black hole. It has a radius about the distance of Mars from the sun, IIRC from the article. Which, if you packed it with stuff at that density, is still a startling lot of mass.
brooksmoses: (Default)

[personal profile] brooksmoses 2008-11-03 07:19 am (UTC)(link)
You're thinking about it in terms of a fixed amount of stuff, which doesn't quite work, for the reasons you're thinking of. In particular, for any given amount of mass there's a corresponding Schwartzchild Radius, and if you compress the mass densely enough to fit within that radius, it's a black hole, and if it's larger so it doesn't fit within that radius, then it's not.

Instead, though, consider taking a sphere of constant density. If you expand the radius of that sphere, then it's got more stuff in it -- the mass of the sphere increases as the radius cubed.

Now, the trick is because of the interesting fact that the Schwartzchild Radius is proportional to the mass of an object.

So, if you take this sphere, and expand it by adding mass, keeping the density constant, then the gravity slope at the edge keeps getting larger, and eventually it will become a black hole -- no matter how non-dense it is.

An intuitive way to think about it is to imagine that you take a sphere, and pick a point on the surface of it. Now, keep that point fixed, and add stuff on the other side of the sphere to make it a larger sphere. All that stuff you're adding is on one side of that point, so it increases the gravity gradient there. Keep adding stuff, and the gradient gets higher and higher, and eventually it will reach the "too steep" state.

[identity profile] browngirl.livejournal.com 2008-11-03 03:50 pm (UTC)(link)
That's a great explanation. Thank you.

*reads and contemplates*
ext_3472: Sauron drinking tea. (quantum)

[identity profile] maggiebloome.livejournal.com 2008-11-03 03:58 am (UTC)(link)
But does the density have to be uniform? Because the universe certainly isn't... and if it DOESN'T have to be, that opens up the possibility that actual black holes that we're aware of have other black holes inside them. Which is a bit of a headache inducing thought. Damn recursion.
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[personal profile] brooksmoses 2008-11-03 07:27 am (UTC)(link)
It doesn't have to be uniform, no. And in general it's not going to be. The article this is from was just noting that, if you put X much stuff within a sphere of size Y or less, then it will be a black hole -- regardless of how you distribute it. And that equation relating Y to X is such that the required average density (computed by taking the volume of Y) goes down -- so that, no matter how low a density you want to talk about, if you fill a large enough sphere Y with it, there will be enough mass of it to be a black hole.
ext_3472: Sauron drinking tea. (Default)

[identity profile] maggiebloome.livejournal.com 2008-11-03 08:09 am (UTC)(link)
Right, so you COULD have a black hole within a black hole within a black hole... whoah...

[identity profile] voltbang.livejournal.com 2008-11-03 04:05 am (UTC)(link)
Very interesting. And the universe is expanding. At some point long ago, it had to be a black hole. Either it is still, or at some point it stopped being a black hole...
brooksmoses: (Default)

[personal profile] brooksmoses 2008-11-03 07:29 am (UTC)(link)
Yup.

Also, in an interesting coincidence, nothing gets out of the universe. :)
geekosaur: orange tabby with head canted 90 degrees, giving impression of "maybe it'll make more sense if I look at it this way?" (Default)

[personal profile] geekosaur 2008-11-03 04:56 am (UTC)(link)
One of the big open questions is whether there is enough mass in the universe to make a cosmic black hole &mdash this is why astronomers are searching for "dark matter" and "dark energy"; many things become simpler if the universe is closed.
brooksmoses: (Default)

[personal profile] brooksmoses 2008-11-03 07:30 am (UTC)(link)
FWIW, I saw this mentioned recently in this recent post on the Bad Astronomy blog. There's a bit more detail on how this works -- and on another nine interesting things about black holes that a lot of people don't know -- in the post.

[identity profile] zachkessin.livejournal.com 2008-11-03 07:49 am (UTC)(link)
The Schwartzchild radius works out to about 3km per solar mass. So a Blackhole of mass 10Msun would have a radius of 30km. One with radius 10E+6MSun would have one of 30,000,000 KM, so since radius scales linearly with the mass, volume must go up like one over R^3.

and before you have a black hole...

(Anonymous) 2008-11-03 01:02 pm (UTC)(link)
The black hole is like the final curtain, which means there is interesting stuff going on before you get to that point. What I find interesting is that "clocks" at the center of a sphere of non-zero density run slower than clocks outside. Postulatin a transparent sphere, then light from the center of the sphere get shifted towards the red. So, if you look at a star a billion light years away, it may be thought of as being in a transparent sphere of non-zero average density. We are at the edge of this large shere and should see a red shift of about 10% of the Hubble red shift.
Dark matter is postulated in part to explain the increasing red shift at extreme distances. Maybe things need to be reexamined?
Duzzy